Interesting box design problem

[Sir_Knumskull]

I found a pretty interesting problem while trying to design my new box. Take a rectangular box with a sloped back side (75 degrees). Place a horizontal divider in the box which seperates it into two volumes. At what height must the divider be placed? I haven't figured out how to do it algebraically. Best I can figure is to make it 2-d, setup an integral and simulate it in matlab. Is there an easier way to do this?

[MarkZ]

I don't get it. What are you trying to achieve? What is the point of the "horizontal divider"? The two subs will be top-bottom or something?

[jakesford]

I don't get it. What are you trying to achieve? What is the point of the "horizontal divider"? The two subs will be top-bottom or something?

ditto...

I'm not sure what you are trying to design?

Try google sketchup: http://www.sketchup.com/ Completely free 3d modeling:cool:

[Sir_Knumskull]

I'm trying to make a TL box. I'm pretty limited on the area it can go in, so I need to get a bit creative with the port. I'm actually sketching it up in solidworks. It's an excuse to use it. :)

[a$$hole]

Sir Knumbskull,

There is quite a lot to TL's

Good luck !

[saMxp]

I just did a quick sketch in UG NX. For a 75 degree angle, the center of the divider needs to be at 46.15% of the volume height to have equal volumes on top and bottom.

[Sir_Knumskull]

I can't say I've tried UG NX before. How is it? Is it more like Catia or Solidworks?

I also found that as I change the height of the trapezoid, the divider location changes. I ended up guessing and checking in solidworks and got it within .5 sqin. Close enough I guess.