thanks for the quick response, the ones in the picture are bcap3000, 3000F at 2.7 volt each, so in series of 6, it's 16.2 volt total. so your suggestion is a balancer for all six should act to distribute all balance voltage charged across all 6 caps, right?
Not to mention once the bank is charged, each capacitors leakage current also causes a different voltage across each capacitor.. Once the bank is fully charged some caps will be undercharged and others will be overcharged, for the voltage to be shared among all 6 capacitors you have to add balancing resistors (6 of them), all 6 resistors combined will act as a voltage divider and counteract the effects of variance in capacitance and leakage current, with no leakage current all 6 capacitors will charge according to the total value of all 6 resistors aka the voltage divider..
Electronics school (Jr College) was a long time ago (30 years) and i have forgotten more than i ever learned but still retained a good bit..
Hi Steven, the original message was too long so here is Part I
Your charging system shouldn't exceed 13.8 volts so you're in good shape there, if those are D Cell Boostcaps the total capacitance should be slightly less than 350 Farads with a 16.2VDC output no voltage limiter is needed because once the capacitors are initially charged because the voltage in the capacitor bank will never drop below 13.8VDC (a 2.3VDC decrease with engine running).. Keep in mind any variance in values of the ESR or equivalent series resistance (low ESR is always better) causes each capacitor to charge at a different rate and to a different voltage and with big electrolytics like the Maxwell Boostcaps you are using the variance can be quite large..