[JohnnyOhh]

you should be good using the diode protected relay by itself, no need to add additional external diodes. Just use the setup as you are describing with that relay you have. it'll be good.

The additional diode that is mentioned in bcae screenshots would do the same thing as the built in protected diode.

the diode protects the metal relay switch contacts themselves (inside the relay) and electronics on the output side of the relay, your dsp remote output would be connected to the input side to energize the coil. the flyback voltage or back emf voltage that would be created during turn-off is only on the output side of the relay & the presence of the built-in diode protects the set-up from it, so you will have no issues. you would be double protected.

also the issue bcae is describing is just talking about the polarity of how you would connect the output side of the load. just use relay only, it will work nice.

what is the part number for the relay? how many devices will you be turning on/off with the relay? how much current draw?

 

[JohnnyOhh]

if you want to rea up on the phenomenon, check this out.

Relay Technical Information (panasonic-electric-works.com) (see p12)

 

[JohnnyOhh]

the bcae article is just saying dont use 2x diodes & then furthermore, do not hook them up backwards to each other if you do have 2x diodes. make sure they are in the same orientation.

but you dont need an external diode anyway, just use the built in one with the relay.

 

[JohnnyOhh]

wait so you had damaged a DSP before? you think it is related to using a relay on the remote output? need more details on that part. what DSP?

So to answer the question accurately....you need to know how much current the DSP remote on pin can supply.... like 0.5A? 1A? the company should be able to tell you that spec.

Then you need to know how much current the relay will draw.... you need to know the coil resistance in order to calculate that. Can you get that info? - This is the smart way to do it.

You need to make sure whatever you hook-up to the remote output will draw less current than the pin can output.

So my relay picture I would be hooking my remote turn on from my DSP to the positive coil side of the relay?

See that's what I'm kind of confused as current flows that direction when I want to not flow in that direction?

And the reason why I'm asking this now is because I had the relay hooked up exactly as it was told to be hooked up you know and now I'm replacing a DSP